3^2-2*3+u=(3^3-3*8)(2)+u

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Solution for 3^2-2*3+u=(3^3-3*8)(2)+u equation: 



3^2-2*3+u=(3^3-3*8)(2)+u

We move all terms to the left:

3^2-2*3+u-((3^3-3*8)(2)+u)=0

We add all the numbers together, and all the variables

u-((3^3-3*8)2+u)+3=0



We calculate terms in parentheses: -((3^3-3*8)2+u), so:

(3^3-3*8)2+u

determiningTheFunctionDomain
u+(3^3-3*8)2

We add all the numbers together, and all the variables

u+6

Back to the equation:

-(u+6)



We get rid of parentheses

u-u-6+3=0

We add all the numbers together, and all the variables

-3!=0

There is no solution for this equation

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